Question # 1
Which task can be performed by using a single Data Manipulation Language (DML)
statement?
| | A. adding a column constraint when inserting a row into a table
| | B. adding a column with a default value when inserting a row into a table
| | C. removing all data only from one single column on which a unique constraint is defined
| | D. removing all data only from one single column on which a primary key constraint is
defined |
C. removing all data only from one single column on which a unique constraint is defined
Question # 2
You need to display the first names of all customers from the CUSTOMERS table that contain the character
‘e’ and have the character ‘a’ in the second last position.
Which query would give the required output?
| | A. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, ‘e’)<>0
ANDSUBSTR(cust_first_name, -2, 1)=’a’;
| | B. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, ‘e’)<>''
ANDSUBSTR(cust_first_name, -2, 1)=’a’;
| | C. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, ‘e’)IS NOT NULL
ANDSUBSTR(cust_first_name, 1, -2)=’a’;
| | D. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, ‘e’)<>0
ANDSUBSTR(cust_first_name, LENGTH(cust_first_name), -2)=’a’; |
A. SELECT cust_first_nameFROM customersWHERE INSTR(cust_first_name, ‘e’)<>0
ANDSUBSTR(cust_first_name, -2, 1)=’a’;
Question # 3
You need to list the employees in DEPARTMENT_ID 20 days in a single row, ordered by HIRE_DATE.
Examine the sample output
Which query will provide the required output?
| | A. SELECT LISTAGG(last_name)WITHIN GROUP ORDER BY (hire_date) “Emp_list”, MIN(hire_date)
“Earliest”FROM employeesWHERE department_id = 30;
| | B. SELECT LISTAGG(last_name, '; ')WITHIN GROUP ORDER BY (hire_date) “Emp_list”,
MIN(hire_date) “Earliest”FROM employeesWHERE department_id = 30;
| | C. SELECT LISTAGG(last_name, '; ') “Emp_list”, MIN(hire_date) “Earliest”FROM employeesWHERE
department_id = 30;WITHIN GROUP ORDER BY (hire_date);
| | D. SELECT LISTAGG(last_name, '; ') “Emp_list”, MIN(hire_date) “Earliest”FROM employeesWHERE
department_id = 30;ORDER BY (hire_date); |
B. SELECT LISTAGG(last_name, '; ')WITHIN GROUP ORDER BY (hire_date) “Emp_list”,
MIN(hire_date) “Earliest”FROM employeesWHERE department_id = 30;
Question # 4
The customers table has the following structure:
You need to write a query that does the following tasks:
1. Display the first name and tax amount of the customers. Tax is 5% of their credit limit.
2. Only those customers whose income level has a value should be considered.
3. Customers whose tax amount is null should not be considered.
Which statement accomplishes all the required tasks? | | A. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNTFROM customersWHERE
cust_income_level IS NOT NULL ANDtax_amount IS NOT NULL;
| | B. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNTFROM customersWHERE
cust_income_level IS NOT NULL ANDcust_credit_limit IS NOT NULL;
| | C. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNTFROM customersWHERE
cust_income_level <> NULL ANDtax_amount <> NULL;
| | D. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNTFROM customersWHERE
(cust_income_level, tax_amount) IS NOT NULL; |
B. SELECT cust_first_name, cust_credit_limit * .05 AS TAX_AMOUNTFROM customersWHERE
cust_income_level IS NOT NULL ANDcust_credit_limit IS NOT NULL;
Question # 5
View the exhibit and examine the structure of the CUSTOMERS table.
Which two tasks would require subqueries or joins to be executed in a single statement?
| | A. finding the number of customers, in each city, whose credit limit is more than the
average credit limit of all the customers
| | B. finding the average credit limit of male customers residing in 'Tokyo' or 'Sydney'
| | C. listing of customers who do not have a credit limit and were born before 1980
| | D. finding the number of customers, in each city, who’s marital status is 'married'.
| | E. listing of those customers, whose credit limit is the same as the credit limit of customers
residing in the city 'Tokyo'. |
A. finding the number of customers, in each city, whose credit limit is more than the
average credit limit of all the customers
E. listing of those customers, whose credit limit is the same as the credit limit of customers
residing in the city 'Tokyo'.
Question # 6
View the exhibit for the structure of the STUDENT and FACULTY tables.
STUDENT
NameNull?Type
-------------------------
STUDENT_IDNOT NULLNUMBER(2)
STUDENT_NAMEVARCHAR2(20)
FACULTY_IDVARCHAR2(2)
LOCATION_IDNUMBER(2)
FACULTY
NameNull?Type
-------------------------
FACULTY_IDNOT NULLNUMBER(2)
FACULTY_NAMEVARCHAR2(20)
LOCATION_IDNUMBER(2)
You need to display the faculty name followed by the number of students handled by the
faculty at the base location.
Examine the following two SQL statements:
Statement 1
SQL>SELECT faculty_name, COUNT(student_id)
FROM student JOIN faculty
USING (faculty_id, location_id)
GROUP BY faculty_name;
Statement 2
SQL>SELECT faculty_name, COUNT(student_id)
FROM student NATURAL JOIN faculty
GROUP BY faculty_name;
Which statement is true regarding the outcome?
| | A. Only statement 2 executes successfully and gives the required result.
| | B. Only statement 1 executes successfully and gives the required result.
| | C. Both statements 1 and 2 execute successfully and give different results.
| | D. Both statements 1 and 2 execute successfully and give the same required result. |
B. Only statement 1 executes successfully and gives the required result.
Question # 7
You want to display 5 percent of the rows from the SALES table for products with the
lowest AMOUNT_SOLD and also want to include the rows that have the same
AMOUNT_SOLD even if this causes the output to exceed 5 percent of the rows.
Which query will provide the required result?
| | A. SELECT prod_id, cust_id, amount_soldFROM salesORDER BY amount_soldFETCH
FIRST 5 PERCENT ROWS WITH TIES;
| | B. SELECT prod_id, cust_id, amount_soldFROM salesORDER BY amount_soldFETCH
FIRST 5 PERCENT ROWS ONLY WITH TIES;
| | C. SELECT prod_id, cust_id, amount_soldFROM salesORDER BY amount_soldFETCH
FIRST 5 PERCENT ROWS WITH TIES ONLY;
| | D. SELECT prod_id, cust_id, amount_soldFROM salesORDER BY amount_soldFETCH
FIRST 5 PERCENT ROWS ONLY; |
A. SELECT prod_id, cust_id, amount_soldFROM salesORDER BY amount_soldFETCH
FIRST 5 PERCENT ROWS WITH TIES;
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