Question # 1
In the customers table, the CUST_CITY column contains the value 'Paris' for the CUST_FIRST_NAME 'Abigail'. Evaluate the following query:
 What would be the outcome?
| A. Abigail PA
| B. Abigail Pa
| C. Abigail IS
| D. An error message |
Question # 2
Examine the structure of the EMPLOYEES table:
 There is a parent/child relationship between EMPLOYEE_ID and MANAGER_ID. You want to display the name, joining date, and manager for all employees. Newly hired employees are yet to be assigned a department or a manager. For them, ‘No Manager’ should be displayed in the MANAGER column. Which SQL query gets the required output? | A. SELECT e.last_name, e.hire_date, NVL(m.last_name, ‘No Manager’) ManagerFROM employees e JOIN employees mON (e.manager_id = m.employee_id);
| B. SELECT e.last_name, e.hire_date, NVL(m.last_name, ‘No Manager’) ManagerFROM employees e LEFT OUTER JOIN employees mON (e.manager_id = m.employee_id);
| C. SELECT e.last_name, e.hire_date, NVL(m.last_name, ‘No Manager’) ManagerFROM employees e RIGHT OUTER JOIN employees mON (e.manager_id = m.employee_id);
| D. SELECT e.last_name, e.hire_date, NVL(m.last_name, ‘No Manager’) ManagerFROM employees e NATURAL JOIN employees mON (e.manager_id = m.employee_id). |
B. SELECT e.last_name, e.hire_date, NVL(m.last_name, ‘No Manager’) ManagerFROM employees e LEFT OUTER JOIN employees mON (e.manager_id = m.employee_id);
Question # 3
View and Exhibit and examine the structure and data in the INVOICE table. (Choose two.)
 Which two statements are true regarding data type conversion in query expressions?
| A. inv_date = '15-february-2008' :uses implicit conversion
| B. inv_amt = '0255982' : requires explicit conversion
| C. inv_date > '01-02-2008' : uses implicit conversion
| D. CONCAT(inv_amt, inv_date) : requires explicit conversion
| E. inv_no BETWEEN '101' AND '110' : uses implicit conversion |
A. inv_date = '15-february-2008' :uses implicit conversion
E. inv_no BETWEEN '101' AND '110' : uses implicit conversion
Question # 4
View the exhibit and examine the structure of the PROMOTIONS table
 You have to generate a report that displays the promo name and start date for all promos that started after the last promo in the ‘INTERNET’ category. Which query would give you the required output?
| A. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date> ALL (SELECT MAX (promo_begin_date)FROM promotions) ANDpromo_category= ‘INTERNET’; | B. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date IN (SELECT promo_begin_dateFROM promotionsWHERE promo_category= ‘INTERNET’);
| C. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date > ALL (SELECT promo_begin_dateFROM promotionsWHERE promo_category = ‘INTERNET’);
| D. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date> ANY (SELECT promo_begin_dateFROM promotionsWHERE promo_category= ‘INTERNET’); |
C. SELECT promo_name, promo_begin_date FROM promotionsWHERE promo_begin_date > ALL (SELECT promo_begin_dateFROM promotionsWHERE promo_category = ‘INTERNET’);
Question # 5
Which three statements are true about defining relations between tables in a relational database?
| A. Primary key columns allow null values.
| B. Every primary or unique key value must refer to a matching foreign key value.
| C. Foreign key columns allow null values.
| D. Every foreign key value must refer to a matching primary or unique key value.
| E. Unique key columns allow null values. |
C. Foreign key columns allow null values.
D. Every foreign key value must refer to a matching primary or unique key value.
Question # 6
View the exhibit and examine the structure of ORDERS and CUSTOMERS tables. ORDERS Name Null? Type ORDER_ID NOT NULL NUMBER(4) ORDER_DATE NOT NULL DATE ORDER_MODE VARCHAR2(8) CUSTOMER_ID NOT NULL NUMBER(6) ORDER_TOTAL NUMBER(8, 2) CUSTOMERS Name Null? Type CUSTOMER_ID NOT NULL NUMBER(6) CUST_FIRST_NAME NOT NULL VARCHAR2(20) CUST_LAST_NAME NOT NULL VARCHAR2(20) CREDIT_LIMIT NUMBER(9,2) CUST_ADDRESS VARCHAR2(40) Which INSERT statement should be used to add a row into the ORDERS table for the customer whose CUST_LAST_NAME is Roberts and CREDIT_LIMIT is 600? Assume there exists only one row with CUST_LAST_NAME as Roberts and CREDIT_LIMIT as 600.
| A. INSERT INTO (SELECT o.order_id, o.order_date, o.order_mode, c.customer_id, o.order_totalFROM orders o, customers cWHERE o.customer_id = c.customer_id AND c.cust_last_name='Roberts' AND c.credit_limit=600)VALUES (1,'10-mar-2007', 'direct', (SELECT customer_idFROM customersWHERE cust_last_name='Roberts' AND credit_limit=600), 1000);
| B. INSERT INTO orders (order_id, order_date, order_mode,(SELECT customer idFROM customersWHERE cust_last_name='Roberts' AND credit_limit=600), order_total);VALUES (1,'10-mar-2007', 'direct', &customer_id, 1000);
| C. INSERT INTO ordersVALUES (1,'10-mar-2007', 'direct',(SELECT customer_idFROM customersWHERE cust_last_name='Roberts' AND credit_limit=600), 1000); | D. INSERT INTO orders (order_id, order_date, order_mode,(SELECT customer_idFROM customersWHERE cust_last_name='Roberts' AND credit_limit=600), order_total);VALUES (1,'10-mar-2007', 'direct', &customer_id, 1000); |
C. INSERT INTO ordersVALUES (1,'10-mar-2007', 'direct',(SELECT customer_idFROM customersWHERE cust_last_name='Roberts' AND credit_limit=600), 1000);
Question # 7
Examine the description of the ORDERS table: Which three statements execute successfully? | A. SELECT ORDER_ID INVOICE_ID ORDER-DATE FROM ORDERS MINUS SELECT INVOICE_ID INVOICE_DATA FROM INVOICE ORDER BY INVOICE_ID; | B. SELECT * FROM ORDERS ORDER BY ORDER_ID UNION SELECT * FROM INVOICES; | C. SELECT ORDER_ID ORDER_DATE FROM ORDERS UION ALL SELECT INVOICE_ID, INVOICE_DATE FROM INVOICE ORDER BY ORDER_ID; | D. SELECT * FROM ORDERS ORDER BY ORDER_ID INTERSECT SELECT * FROM INVOICE ORDER BY INVOICE_ID; | E. (SELECT * FROM ORDERS |
A. SELECT ORDER_ID INVOICE_ID ORDER-DATE FROM ORDERS MINUS SELECT INVOICE_ID INVOICE_DATA FROM INVOICE ORDER BY INVOICE_ID; C. SELECT ORDER_ID ORDER_DATE FROM ORDERS UION ALL SELECT INVOICE_ID, INVOICE_DATE FROM INVOICE ORDER BY ORDER_ID;
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